name   group   group_value
M       A         1
M       B         2
M       dev       4
D       etc.......


select name, sum(group_value) from test
  group by name
  having group_value = (select sum(group_value) from test where name =
'M'));

should work (off of the top of my head and my typing is not tested.)

Notice those group_values are disjoint powers of two. You could craft a
decode on your existing data to do the same thing. If you don't enforce
uniqueness on name-group tuples this could generate false answers, and you'd
have to make the statement more complicated.

-----Original Message-----
From: oracle-l-bounce@(protected)
Behalf Of David Boyd
Sent: Monday, July 10, 2006 11:18 AM
To: oracle-l@(protected)
Subject: SQL help needed

Hi List,

I was wondering if a SQL statement is possible for following query.

The name of the table is test. It has following data:

name                group
Marry                group A 1-1
Marry                group B 1-2
Marry                group dev 1-1
Ann                 group A 2-3
Dave                 group A 2-3
Dave                 group B 4-1
Dave                 group dev 3-2

I want to find out the names that are in the exact same groups as 'Marry'.
The number in the group has to be ignored. For the above data, the query
should return 'Dave' only since both Marry and Dave are in group A, group B,
and group dev.

Thanks for any input advance.

Dave

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